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**Home ⇒ Overview Courses ⇒ Electrical engineering ⇒ Resistors in a Mixed Connection**

### Resistors in a Mixed Connection

Look at which resistors are in parallel or in series and summarize them. Work from "inside" to "outside". Here is an example: The expected measurement voltage is to be calculated. Therefor, you have to determine the total resistance:

**Step 1:** R_{1}, R_{2} and R_{3} are parallel and can be combined to form a substitute response R_{1,2,3}.

R_{1,2,3} = R_{1}/3 = 300 Ω / 3 = 100 Ω

**Step 2:** You can now see that R_{1,2,3} and R_{4} are in series. The equivalent resistance R_{1,2,3,4} can easily be determined by addition:

R_{1,2,3,4} = R_{1,2,3} + R_{4} = 100 Ω + 150 Ω = 250 Ω

This results in the following equivalent circuit:

**Step 3:** Now we dissolve the parallel connection of R_{1,2,3,4} and R_{5}:

R_{1,2,3,4,5} = R_{1,2,3,4} * R_{5} = 250 Ω * 300 Ω = 136,36 Ω

. R_{1,2,3,4} + R_{5} 250 Ω + 300 Ω

**Step 4:** What remains is a simple series connection. Calculating the total current which flows through R_{6} is now a simple exercise:

R_{t} = R_{1,2,3,4,5} + R_{6} = 136,36 Ω + 200 Ω = 336,36 Ω

I_{t} = I_{R6} = U = 24 V = 71,35 mA

. R_{t} 336,36 Ω

=> V_{Measure} = U_{R6} * I_{t }= 200 Ω * 71,35 mA = 14,27 V