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- Electrical engineering
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Solutions:
Work order 1:
1.1 Delta connection
1.2 P = √3 U I You use the line-values; here cosφ = 1, because you have purely ohmic resistances
=> I = P / (√3 U) = 10000W / (√3 400V) = 14,43 A
1.3 Ptotal = 3 UPhase * IPhase = 3 U2Phase / RPhase => RPhase = 3 U2Phase / PPhase = 3 * 4002V2 / 10000W = 48 Ω
Work order 2:
2.1 IPhase = U / R with U = UPhase, because you have Delta and
IStr = U / R = 400V / 80Ω = 5A
2.3 I = 8,66A
2.4 Ptotal = 6 kW
2.5 RTotal = 2R || R = 160Ω * 80Ω / (160Ω + 80Ω)
Aufgabe 3:
3.1 Delta
3.2 U = UPhase = R * IPhase = 80Ω * 5A = 400V
3.3 I = √3 * IPhase = √3 * 5A = 8,66A
3.4 P = 3 PPhase = 3 R * I2Phase = 3 * 80Ω * 52A * = 6 kW
3.5 See work order 2