PLC-exercises II – boolean algebra

Boolean Algebra exercises

---

Boolean Algebra exercise 1

Derive the switching algebra expression that corresponds one to one with the circuit as shown.

 a Λ (b Λ c V d) = y

 a Λ b Λ c V d = y

 a Λ [(b Λ c) V d] = y

 a Λ (b V d) = Y

 a Λ b V d = y

 Loading …

Exercise 1

Simplify the circuit shown using Boolean algebra and check your result with a KV-diagram!

Exercise Simplification by Boolean algebra and KV diagram 1

Exercise 2

Simplify the following boolean equation using Boolean algebra!

Boolean Algebra exercise 2

Exercise 3

Simplify the circuit shown using Boolean algebra and check your result with a KV-diagram!

Boolean Algebra exercise 3

Exercise 4

Simplify the following boolean equation using Boolean algebra and proof your result with a KV-diagram:

Exercise 5

Simplify the following boolean equation using Boolean algebra:

Exercise 6

Determine the simplified Boolean equation from the following digital circuit. There are two ways to solve this:

1. Determine the equations at the output of each individual gate.
2. Use a truth table

=>  Get the solutions