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Operational Amplifier as Differential Amplifier
Table of Contents
ToggleDerivation of the equation for the output voltage considering that all 4 resistors R1 to R4 are of different values:
Case: VIN1 = 0 and thus Vi- = 0:
Calculation of Vi+ via voltage divider:
For the partial output voltage VOUT+ you get:
Eq. (1) in Eq. (2) results in
Case: VIN2 = 0 and therefore Vi+ = 0:
Bringing together equations (3) and (4):
If the input voltage in both inputs should be acquired in the same way:
The symmetry of the resistors must be right, i.e. the resistance ratios R1=R2 and R3=R4 must apply so that the operational amplifier, as a differential amplifier, acquires the same voltages at its inputs in the same way:
Exercise:
In the following circuit you see a differential amplifier using an OP-amp. Calculate the resistor R4.
I1 = VR1 = VOUT - Vin1 ⇒ VR1 = (5V - 2V) × 47 kΩ = 0,4913 V V+ = VIN1 + VR1 = 2V + 0,4913V = 2,4913V V- = V+ ⇒ V+ = 2,4913 V VR3 = VIN2 - V+ = 9V - 2,4913 V = 6,5087 V VR4 = V+ = 2,4913V I2 = VR3 = V+ ⇒ R4 = V+ × R3 = 2,4913 V × 131 kΩ = 50 kΩ
. R1 R1 + R2
. 287 kΩ
. R3 R4
VR3 6,5087 V