**The basic laws of pneumatics**

Without pressure nothing works!

Patmospheric pressure, that means the pressure at sea level_{atm}

Patmospheric differential pressure_{Gauge}

P_{abs}Pressure in absolute numbers in relation to 0 bar or vacuum. (abb. frompressure absolute)

Units:Pascal (Pa) represents the pressure unit of the International System of Units (SI), but in industrial practice, pressure is represented in bar or pounds per square inch (PSI).

1 bar = 10^{5}Pa =14.5 PSI

1 Pascal=1 Newton

1 m^{2}

1 PSI=1 pound1 in

^{2}

**The law of physics according to Boyle-Mariotte (Robert Boyle e Edna Mariotte)**

The air, which is condensed has the effort to generate pressure. In other words, the bigger the compression, the bigger the pressure (assuming temperature remains constant):

**p ~ 1 / V** at **T = constant** (**Isothermal curve**): Each curve belongs to a certain temperature and is therefore called isotherm. The curves form a hyperbola. You can explain this behaviour by regarding the air particles as molecules, which bump against the vessel wall. If the volume is reduced, these particles are given less space. So they will strike more often against the vessel wall and thereby the mean force increases.

#### Law of Gay Lussac (Joseph Louis gay Lussac)

**V ~ T** at p =** const. (Isobar change)**: If the pressure p is to be kept constant, then the particles have to be given larger volumes at higher temperatures. The straight lines (V ~ T) are called **isobars**.

#### Law of Charles (Jacques Alexandre Charles)

**p ~ T at V = const.** (**Isochronic curve**): The explanation is simple: the higher the temperature, the higher the velocity of the particles, and the more often these particles strike the vessel wall. The lines (p ~ T) are called **isochors**.

**General gas equation**

Gas has the property of expanding when the temperature increases. The general gas equation takes into account the influence of temperature on a closed gas quantity.

**p**

_{1}* V_{1}= p_{2}* V_{2}**T**

_{1}T_{2}**.**

**.**

**.**

**Exercises for chapter 2:**

**2A1:** For a plant, a working pressure of 6 bar refering to the norm-pressure of 1.01325 bar is to be generated. What must be P_{abs}?

**2A2:** A compressor compresses the ambient air to 1/8 of its volume. What pressure will be achieved by the simplification that the temperature remains constant?

**A1:** p_{abs} = p_{amb} + p_{e} = 1,01325 bar + 6 bar = __7,01325 bar__

**A2: ** p_{1} * V_{1} = p_{2} * V_{2} p_{1} = p_{amb} = 1 bar

p_{2} = (p_{1} * V_{1}_{ }) / V_{2} => p_{2} = 1 bar * 8 /1= 8 bar

=> p_{e} = p_{abs} – p_{amb} = 8 bar – 1 bar = __7 bar__