Solution basics electrics

Solution basics electrics

Exercise 1:

DC voltage network exercise 1

R₁ = 8 Ω, R₂ = 1 Ω, R₃ = R₄ = R₅ = 3 Ω, R₆ = 2,5 Ω, I = 10 A

Calculate the voltage V_I and the voltage drop across resistor R₆.

R₄₅ = R/2 = 1,5 Ω         
R₄₅₆ = R₄₅ + R₆ = 4 Ω
R₂₃ = R₂ + R₃ = 4 Ω
R₂₃₄₅₆ = R₂₃ || R₄₅₆   = 2 Ω
R_total = R₂₃₄₅₆ + R₁ = 10 Ω

V_i = R_total · I = 10 Ω · 10 A = 100 V

V₂₃₄₅₆ = R₂₃₄₅₆ · I = R₄₅₆ · I₄₅₆ 

I₄₅₆ = R₂₃₄₅₆ · I = 2 Ω · 10 A  = 5 A
.             R₄₅₆           4 Ω

V_R6 = R₆ · I₆ = 2,5 Ω · 5 A = 12,5 V