Home ⇒ Overview Courses ⇒ Electronics ⇒ Operational amplifier ⇒ Transimpedance amplifier
Transimpedance amplifier
Table of Contents
ToggleThe following circuit, which is referred to as a current-voltage converter or transimpedance converter (TIA), converts an input current IIN into a defined output voltage VOUT:
The basis of the current-voltage converter is the inverting amplifier. Since the input current of the OP-Amp is negligibly small, we derive from the node rule:
IIN = - If
Applying the law of Ohm:
VOUT = Vf = If × Rf = - IIN × R
This makes it clear that the output voltage is proportional to the input current. The ratio of input current to output voltage is determined by the resistance Rf.
Exercise Op-Amp as Transimpedance Amplifier
Below you can see an Op-Amp circuit that converts a sensor signal of 4 ... 20 mA into a voltage signal of 0 to 10 V.
- What tasks do these two Op-Amp´s have in this circuit?
- What advantage does a sensor with a current signal of 4 to 20 mA offer compared to a sensor with a voltage signal of 0 to 10 V?
- In the diagram below, add the characteristic curve V1 depending on the sensor signal!
1. Op-Amp 1 as transimpedance - Converter, Op-Amp 2 as summer
2. Current signal can also be kept constant or stable via a long signal line. Minimum current 4 mA means wire break protection.
3. See diagram below: