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OP Amp as Non-Inverting Amplifier
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ToggleHere the output signal is fed back to the inverting input by a voltage divider. The output signal is divided by the voltage divider, which results in an output signal being amplified. The resistance ratio determines the gain factor.
Since the input resistance of an operational amplifier is very high, the input currents are negligible. Thus: I1 = I2 (1)
Since the differential voltage at the inputs of the operational amplifier is zero, the following applies: VR1 = VIN (2)
Apply the mesh rule and you get for the output voltage VOUT:
VOUT = VR1 + VR2 or VOUT = VIN + VR2
With I1 = I2 and Ohm's law you get:
Exercise - OP-Amp as Non-Inverting Amplifier
Exercise 1:
Calculate the output voltage with the following values: R1 = 2 kΩ, R2 = 22 kΩ, VIN = - 500 mV
Exercise 2:
R1 = 2 kΩ, R2 = 22 kΩ, Ue = 1 V
- What voltage is measured between the inverting and the non-inverting input in the steady state ?
- Calculate the current flowing through R2 ?
- What is the voltage drop across R2?
Solution exercise 1:
Vout = (1 + R1 / R2) VIN = (1 + 22 kΩ / 2 kΩ) (-) 0.5 V = - 6V
Solution exercise 2:
The difference between the two inputs of the Op-Amp is in the steady state: Udiff = 0V
Since the input current of the Op-Amp is negligibly small, the following applies: I1 = I2
I2 = I1 = VR1 / R1 = VIn / R1 = 1 V / 2 kΩ = 0.5 mA
VR2 = I2 * R2 = 0.5 mA * 22 kΩ = 11 V