**Work order: Parameterize the frequency inverter **

*auxiliary aid: Technical Data Manual*

In order to enable a smooth start and stop, the drive for the conveyor belt is controlled by a VFD. Your work order is to understand the information of the motor rating plate and to determine the correct parameters for the VFD.

**A1: **Explain the information given on the rating plate.

**A2:** How should the motor be switched on our three-phase network 400 V / 230 V if you would connect it directly (Star or Delta)? Please give a short explanation!

**A3: **Determine slip, slip speed and efficiency for nominal operation and operating frequency f = 50 Hz.

**A4: **So that the belt starts and stops smoothly, choose a frequency converter. According to the manufacturer, the following motor parameters must be entered for initial commissioning:

P0304: nominal voltage

P0305: nominal current

P0307: nominal power

P0308: nominal power factor

P0310: nominal frequency

P0311: nominal speed

Enter the specific values. Missing values you have to calculate.

**A5: **The workpiece carriers (workpiece carriers) should be conveyed at a maximum speed of 0.4 m/s. For starting the acceleration for the belt should be 0.10 m/s^{2}. When stopping, the deceleration should be 0.25 m/s^{2}. To which values do you have to set the VFD parameters P0320 (ramp-up time) and P0321 (ramp-down time)?

**A2:** If two voltages are specified on the motor rating plate, the lower voltage stands for the permissible phase voltage (voltage at the motor coils). That´s why the motor must be connected in star to a 400V supply voltage.

**A3: **n_{slip} = n_{s}-n_{N} = 1500min^{-1} – 1400 min^{-1} = __100 min ^{-1}__

slip s = (n_{s} – n_{N}) / n_{s} * 100% = __10 %__

η = P_{mech} / P_{electr }= 0,16 kW / 0,2106 kW = __0,76__

(P_{zu} = √3 U * I *cosφ = √3 * 400V * 0,4A * 0,76 = __0,2106 kW)__

**A4: ** Just watch the motor plate

**A5:** Within the v(t)-diagram, the ramps represent a uniform acceleration.

=> v(t) = a * t *remark: v stands for „velocity“ and a for „acceleration“*

=> t_{Start} = v_{max} / a_{1} = 0,4 m/s / 0,1 ms^{2} = __4 s__

=> t_{Stopp} = v_{max} / a_{2} = 0,4 m/s / 0,25 ms^{2} = __1,6 s__