Solution Wheatstone Bridge with NTC

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Solution:

a) R4(ϑ = 0°C) ≈ 170 kΩ => R3 = 170 kΩ

b) V_BR = V2 - V4 ¦ R4 (ϑ = 100°C) ≈ 3,5 kΩ

. V4 = R4 * V = 3,5 kΩ * 6V = 0,1210 V
. R3 + R4 (170 kΩ + 3,5 kΩ)

. V_BR = 3V - 0,1210 V = 2,879 V

V = V_Meß / V_BR ¦ Cond.: V_Meas (ϑ = 100°C) = 10 V

. => V = 10 V / 2,879V = 3,473